Class 12 Chemistry Alcohol Notes

Unit 10
Organic Chemistry
Class 12 Chemistry

Alcohol

On mobile, swipe inside the PDF to read all pages and pinch to zoom.

NEB/CDC syllabus scope: Unit 10 covers introduction; nomenclature, isomerism and classification of monohydric alcohols; Victor Meyer’s method for distinguishing primary, secondary and tertiary alcohols; preparation from haloalkanes, primary amines and esters; industrial preparation by oxo process, hydroboration–oxidation and fermentation; common alcohol terms; physical properties; reactions with hydrogen halides and phosphorus/thionyl halides; action with reactive metals; dehydration; oxidation; catalytic dehydrogenation/dehydration; esterification; and tests of ethanol.

1. Introduction to Alcohols

Definition Alcohols are organic compounds in which one or more hydroxyl groups (–OH) are attached to saturated sp³-hybridized carbon atoms.
General representation R–OH

For a saturated open-chain monohydric alcohol, the molecular formula can be written as:

CnH2n+1OH

Examples:

CH₃OH = methanol CH₃CH₂OH = ethanol CH₃CH₂CH₂OH = propan-1-ol
Alcohol vs Phenol In an alcohol, –OH is attached to an sp³ carbon. In phenol, –OH is attached directly to an aromatic sp² carbon. They are treated as different functional classes because their chemical behaviour differs substantially.

2. Classification of Alcohols

2.1 Based on Number of –OH Groups

TypeNumber of –OH groupsExample
Monohydric1CH₃CH₂OH
Dihydric2HOCH₂CH₂OH
Trihydric3HOCH₂CHOHCH₂OH
PolyhydricMore than 3Compounds with several –OH groups

2.2 Primary, Secondary and Tertiary Monohydric Alcohols

The classification depends on how many carbon atoms are directly attached to the carbon bearing –OH.

TypeGeneral formExample
Primary (1°)R–CH₂OHCH₃CH₂OH
Secondary (2°)R₂CHOHCH₃CHOHCH₃
Tertiary (3°)R₃COH(CH₃)₃COH
Classification of Monohydric Alcohols Primary (1°) R–CH₂–OH OH-carbon attached to one carbon Example: ethanol Secondary (2°) R₂CH–OH OH-carbon attached to two carbons Example: propan-2-ol Tertiary (3°) R₃C–OH OH-carbon attached to three carbons Example: tert-butanol Always inspect the carbon directly carrying the –OH group.

Diagram 1: Primary, secondary and tertiary alcohols

3. Nomenclature and Isomerism

3.1 IUPAC Nomenclature

  1. Select the longest carbon chain containing the carbon bearing –OH.
  2. Replace the terminal “e” of the parent alkane with “ol”.
  3. Number the chain so the –OH group receives the lowest possible locant.
  4. Indicate substituents with their positions.
FormulaIUPAC nameCommon name
CH₃OHMethanolMethyl alcohol
CH₃CH₂OHEthanolEthyl alcohol
CH₃CH₂CH₂OHPropan-1-oln-Propyl alcohol
CH₃CHOHCH₃Propan-2-olIsopropyl alcohol
(CH₃)₃COH2-Methylpropan-2-oltert-Butyl alcohol

3.2 Isomerism

Monohydric alcohols may show:

  • chain isomerism — different carbon skeleton;
  • position isomerism — different position of –OH;
  • functional isomerism with ethers for suitable molecular formulae;
  • optical isomerism where a chiral carbon is present.
Example: C₃H₈O CH₃CH₂CH₂OH = propan-1-ol CH₃CHOHCH₃ = propan-2-ol

These are position isomers. Methoxyethane, CH₃OCH₂CH₃, is a functional isomer of the alcohols.

4. Distinction of 1°, 2° and 3° Alcohols by Victor Meyer’s Method

Victor Meyer’s method distinguishes primary, secondary and tertiary alcohols through conversion to characteristic nitro compounds followed by treatment with nitrous acid and alkali.

General Steps

  1. Convert the alcohol into the corresponding alkyl iodide.
  2. Convert the alkyl iodide into a nitroalkane using silver nitrite.
  3. Treat the product with nitrous acid.
  4. Add alkali and observe the colour.
Alcohol typeIntermediate behaviourObservation after alkali
Primary (1°)Forms nitrolic acidBlood-red colour
Secondary (2°)Forms pseudonitrolBlue colour
Tertiary (3°)Does not form the corresponding nitrolic-acid/pseudonitrol systemNo characteristic red/blue colour
Victor Meyer’s Method Unknown alcohol Alcohol → alkyl iodide then AgNO₂ → nitroalkane Treat with HNO₂ then add alkali 1° alcohol nitrolic acid blood-red 2° alcohol pseudonitrol blue 3° alcohol no characteristic derivative no red/blue colour Observation of colour is used to identify the alcohol class.

Diagram 2: Victor Meyer test flowchart

Exam Important Memorize the final observations: 1° = red, 2° = blue, 3° = no characteristic colour.

5. Preparation of Monohydric Alcohols

5.1 From Haloalkanes

Aqueous hydroxide replaces halogen by –OH:

R–X + KOH(aq) → R–OH + KX

Example

C₂H₅Br + KOH(aq) → C₂H₅OH + KBr

5.2 From Primary Amines

Primary aliphatic amines react with nitrous acid to give alcohols with evolution of nitrogen gas.

R–NH₂ + HNO₂ → R–OH + N₂↑ + H₂O

Example

C₂H₅NH₂ + HNO₂ → C₂H₅OH + N₂ + H₂O

5.3 From Esters

Hydrolysis of an ester produces an alcohol and a carboxylic acid (or carboxylate in alkaline hydrolysis).

RCOOR′ + H₂O ⇌ RCOOH + R′OH
Laboratory Preparation of Alcohols R–OH alcohol Haloalkane R–X + aq. KOH Primary amine R–NH₂ + HNO₂ Ester hydrolysis

Diagram 3: Preparation from haloalkanes, primary amines and esters

6. Industrial Preparation of Alcohols

6.1 Oxo Process

In the oxo process (hydroformylation), an alkene reacts with carbon monoxide and hydrogen to form an aldehyde. The aldehyde is then hydrogenated to an alcohol containing one more carbon atom than the starting alkene.

RCH=CH₂ + CO + H₂ → RCH₂CH₂CHO / branched aldehyde RCH₂CH₂CHO + H₂ → RCH₂CH₂CH₂OH
Important Note Real industrial hydroformylation may form both normal and branched aldehydes depending on catalyst and conditions. For school-level study, focus on the principle: alkene → aldehyde → alcohol.
Oxo Process Alkene RCH=CH₂ Aldehyde + one carbon Alcohol hydrogenated product CO + H₂ H₂ Hydroformylation adds a formyl carbon; hydrogenation gives the alcohol.

Diagram 4: Oxo-process principle

6.2 Hydroboration–Oxidation

Hydroboration followed by oxidation converts an alkene into an alcohol. The net addition places –OH at the less substituted carbon in the usual anti-Markovnikov orientation.

CH₂=CH₂ → CH₃CH₂OH   [1. BH₃; 2. H₂O₂/OH⁻]
Hydroboration–Oxidation CH₂=CH₂ ethene CH₃CH₂OH ethanol 1. BH₃ 2. H₂O₂ / OH⁻ Alkene → alcohol without carbocation rearrangement.

Diagram 5: Hydroboration–oxidation of ethene

6.3 Fermentation of Sugar

Yeast enzymes convert fermentable sugars into ethanol and carbon dioxide under suitable anaerobic conditions.

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

The process typically requires an aqueous sugar solution, yeast and controlled temperature. Industrial ethanol is separated and concentrated after fermentation.

Fermentation of Sugar C₆H₁₂O₆ glucose Yeast enzymes controlled conditions low oxygen 2C₂H₅OH + 2CO₂ ethanol + carbon dioxide C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

Diagram 6: Fermentation of glucose

7. Common Terms Related to Ethanol

TermMeaning
Absolute alcoholEthanol essentially free from water; very high-purity ethanol.
Rectified spiritConcentrated ethanol–water mixture obtained by fractional distillation, approximately the constant-boiling ethanol–water composition.
Denatured alcohol / methylated spiritEthanol deliberately made unsuitable for drinking by adding denaturants; exact formulations vary by regulation.
Power alcoholA fuel blend containing ethanol with petrol/gasoline, historically described for internal-combustion engines.
Alcoholic beverageA beverage containing ethanol produced by fermentation and/or further processing. This is a definition only; alcohol consumption carries health and legal considerations.
Important Do not confuse absolute alcohol with rectified spirit. Absolute alcohol is nearly water-free ethanol, whereas rectified spirit still contains a significant small proportion of water because ordinary distillation reaches an ethanol–water azeotrope.

8. Physical Properties of Monohydric Alcohols

Alcohols contain a polar O–H bond and can form intermolecular hydrogen bonds. This strongly affects boiling point and water solubility.

Intermolecular Hydrogen Bonding in Alcohols R–O H O–H–R hydrogen bond O–H donor oxygen lone-pair acceptor Hydrogen bonding raises boiling points and increases water affinity of lower alcohols.

Diagram 7: Intermolecular hydrogen bonding

PropertyTrend / explanation
StateLower alcohols are colourless liquids; higher homologues may become more viscous or solid-like.
Boiling pointHigher than corresponding hydrocarbons/ethers because alcohol molecules hydrogen-bond.
Boiling point down seriesGenerally rises as molecular mass and dispersion forces increase.
Water solubilityLower alcohols are highly soluble because of hydrogen bonding with water.
Solubility down seriesDecreases as the non-polar hydrocarbon part becomes larger.
Why does ethanol boil higher than ethoxyethane? Ethanol molecules form strong intermolecular hydrogen bonds through O–H groups. Ethers cannot donate O–H hydrogen bonds to one another, so less energy is required to separate ether molecules.

9. Chemical Properties: Replacement of –OH by Halogen

9.1 Reaction with Hydrogen Halides

ROH + HX → RX + H₂O

Example

C₂H₅OH + HBr → C₂H₅Br + H₂O

9.2 With Phosphorus Trihalides

3ROH + PCl₃ → 3RCl + H₃PO₃

9.3 With Phosphorus Pentachloride

ROH + PCl₅ → RCl + POCl₃ + HCl

9.4 With Thionyl Chloride

ROH + SOCl₂ → RCl + SO₂ + HCl
Why SOCl₂ is convenient in laboratory preparation Its by-products SO₂ and HCl are gaseous under ordinary reaction work-up conditions, so the organic chloride can often be separated more easily.

10. Action with Reactive Metals

Alcohols react with strongly electropositive metals such as sodium, potassium and lithium to form alkoxides and hydrogen gas.

2ROH + 2Na → 2RONa + H₂↑

Example

2C₂H₅OH + 2Na → 2C₂H₅ONa + H₂↑
Alkoxide An alkoxide is the conjugate base of an alcohol, represented as RO⁻; sodium ethoxide is C₂H₅ONa.
Remember The O–H hydrogen is replaced by metal. The carbon skeleton is unchanged.

11. Dehydration of Alcohols

Dehydration Elimination of water from an alcohol to produce an alkene, usually using concentrated H₂SO₄ and heat or a suitable solid acid catalyst.

11.1 Ethanol to Ethene

CH₃CH₂OH → CH₂=CH₂ + H₂O   (conc. H₂SO₄, heat)

11.2 Orientation in Unsymmetrical Alcohols

Where more than one alkene can form, the more substituted alkene is commonly the major product under ordinary Saytzeff-type conditions.

Dehydration of an Alcohol CH₃–CH(OH)–CH₂–CH₃ butan-2-ol conc. H₂SO₄ / heat CH₃–CH=CH–CH₃ but-2-ene, major CH₂=CH–CH₂–CH₃ but-1-ene, minor Water is eliminated from adjacent carbon atoms.

Diagram 8: Dehydration and alkene formation

12. Oxidation of Primary, Secondary and Tertiary Alcohols

Acidified potassium dichromate or potassium permanganate can oxidize alcohols. The products depend strongly on whether the alcohol is primary, secondary or tertiary.

12.1 Primary Alcohol

RCH₂OH + [O] → RCHO + H₂O RCHO + [O] → RCOOH

Thus a primary alcohol first gives an aldehyde and, under stronger/prolonged oxidation, a carboxylic acid.

12.2 Secondary Alcohol

R₂CHOH + [O] → R₂C=O + H₂O

A secondary alcohol gives a ketone.

12.3 Tertiary Alcohol

Tertiary alcohols do not have a hydrogen on the carbon bearing –OH. They therefore resist mild oxidation that leaves the carbon skeleton intact. Strong conditions can cause carbon–carbon bond cleavage, but that is beyond the simple school-level oxidation pattern.

Oxidation Pattern of Alcohols 1° alcohol RCH₂OH 2° alcohol R₂CHOH 3° alcohol R₃COH Aldehyde RCHO Ketone R₂C=O No simple oxidation with mild oxidant Carboxylic acid RCOOH [O] [O] mild [O] further [O]

Diagram 9: Oxidation products of 1°, 2° and 3° alcohols

Core oxidation rule 1° → aldehyde → acid; 2° → ketone; 3° → resistant to mild oxidation.

13. Catalytic Dehydrogenation and Dehydration

When alcohol vapour is passed over heated copper, primary and secondary alcohols undergo dehydrogenation, while tertiary alcohols preferentially dehydrate because no suitable α-hydrogen is available for the same dehydrogenation pattern.

13.1 Primary Alcohol

RCH₂OH → RCHO + H₂   (Cu, about 573 K)

13.2 Secondary Alcohol

R₂CHOH → R₂CO + H₂   (Cu, about 573 K)

13.3 Tertiary Alcohol

R₃COH → alkene + H₂O   (heated catalyst)
Alcohol Vapour over Heated Copper 1° alcohol RCH₂OH 2° alcohol R₂CHOH 3° alcohol R₃COH Aldehyde + H₂ dehydrogenation Ketone + H₂ dehydrogenation Alkene + H₂O dehydration Primary and secondary alcohols lose H₂; tertiary alcohols readily lose H₂O.

Diagram 10: Catalytic behaviour of different alcohol classes

14. Esterification Reaction

Esterification An alcohol reacts reversibly with a carboxylic acid in the presence of an acid catalyst to produce an ester and water.
RCOOH + R′OH ⇌ RCOOR′ + H₂O   (conc. H₂SO₄)

Example: Ethyl Ethanoate

CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
Observation Many low-molar-mass esters have pleasant fruity odours, so ester formation is often recognizable by smell in controlled laboratory demonstrations. Direct smelling of chemicals should follow laboratory safety procedures.

15. Test of Ethanol

15.1 Iodoform Test

Ethanol gives a positive iodoform test with iodine in alkaline solution. A yellow precipitate of iodoform, CHI₃, is formed.

Positive observation Yellow crystalline precipitate of iodoform (CHI₃) with its characteristic odour.

A commonly written overall equation is:

CH₃CH₂OH + 4I₂ + 6NaOH → CHI₃↓ + HCOONa + 5NaI + 5H₂O
Iodoform Test for Ethanol Ethanol CH₃CH₂OH I₂ + NaOH warm gently CHI₃↓ yellow precipitate positive test Ethanol is one of the alcohols that gives the iodoform test.

Diagram 11: Iodoform test for ethanol

Important Exception The iodoform test is not unique to ethanol. Compounds containing the CH₃CO– group, and alcohols oxidizable to that group (such as propan-2-ol), can also give a positive test. Therefore it is a useful test for ethanol in context, but not a universal proof by itself.

16. High-Yield Reaction Summary

ReactionGeneral equation / resultKey point
With HXROH + HX → RX + H₂O–OH replaced by X
With PCl₅ROH → RClForms POCl₃ and HCl
With SOCl₂ROH → RClSO₂ and HCl by-products
With Na2ROH + 2Na → 2RONa + H₂Alcohol shows weak acidic O–H hydrogen
DehydrationAlcohol → alkene + H₂OAcid + heat
Oxidation of 1°1° alcohol → aldehyde → acidControlled vs stronger oxidation
Oxidation of 2°2° alcohol → ketoneCarbonyl product
Mild oxidation of 3°No simple reactionNo α-H on OH-carbon
Cu dehydrogenation of 1°1° alcohol → aldehyde + H₂Heated copper
Cu dehydrogenation of 2°2° alcohol → ketone + H₂Heated copper
EsterificationRCOOH + R′OH ⇌ RCOOR′ + H₂OAcid catalyst
Ethanol testI₂/NaOH → CHI₃↓Yellow iodoform precipitate

17. Common Exam Mistakes

  • Calling phenol an alcohol simply because it contains –OH. Phenol has –OH directly bonded to an aromatic sp² carbon.
  • Classifying 1°, 2° and 3° alcohols by the total number of carbons rather than by the carbon bearing –OH.
  • Forgetting Victor Meyer observations: 1° red, 2° blue, 3° no characteristic colour.
  • Writing alcoholic KOH for preparation of alcohol from a haloalkane. Aqueous KOH favours substitution to alcohol.
  • Confusing hydroboration–oxidation with hydration under Markovnikov conditions.
  • Confusing absolute alcohol with rectified spirit.
  • Writing NaOH instead of Na metal in the alcohol-to-alkoxide reaction.
  • Oxidizing a secondary alcohol to a carboxylic acid without carbon–carbon cleavage; the normal mild product is a ketone.
  • Writing tertiary alcohol → ketone under mild oxidation. Tertiary alcohols resist simple mild oxidation.
  • Confusing dehydration (loss of H₂O) with dehydrogenation (loss of H₂).
  • Forgetting concentrated acid and heat in dehydration.
  • Calling the iodoform test unique to ethanol. Other suitable compounds also give CHI₃.

18. Worked Examples

Worked Example 1: Classify CH₃CHOHCH₂CH₃

The carbon bearing –OH is attached to two other carbon atoms.

Answer: secondary (2°) alcohol; IUPAC name = butan-2-ol.

Worked Example 2: Oxidation of propan-1-ol CH₃CH₂CH₂OH + [O] → CH₃CH₂CHO + H₂O

Product on controlled oxidation: propanal.

CH₃CH₂CHO + [O] → CH₃CH₂COOH

Further oxidation: propanoic acid.

Worked Example 3: Oxidation of propan-2-ol CH₃CHOHCH₃ + [O] → CH₃COCH₃ + H₂O

Answer: propanone is formed.

Worked Example 4: Alcohol to alkene CH₃CH₂OH → CH₂=CH₂ + H₂O

Use concentrated H₂SO₄ and heat. This is dehydration, not dehydrogenation.

Worked Example 5: Ethanol to ethyl ethanoate CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O

Concentrated H₂SO₄ acts as an acid catalyst/dehydrating medium.

19. Important Exam Questions

Short-Answer Questions

  1. Define alcohol and monohydric alcohol.
  2. Classify monohydric alcohols as primary, secondary and tertiary with examples.
  3. Give IUPAC names of CH₃CH₂OH, CH₃CHOHCH₃ and (CH₃)₃COH.
  4. What kinds of isomerism are shown by monohydric alcohols?
  5. State the observations for 1°, 2° and 3° alcohols in Victor Meyer’s method.
  6. How is ethanol prepared from bromoethane?
  7. How is an alcohol formed from a primary amine?
  8. How does ester hydrolysis produce an alcohol?
  9. What is the oxo process?
  10. What is hydroboration–oxidation?
  11. Write the fermentation equation for glucose.
  12. Define absolute alcohol and rectified spirit.
  13. What is denatured alcohol?
  14. Why do alcohols have comparatively high boiling points?
  15. Why does solubility of alcohols in water decrease with increasing alkyl-chain length?
  16. Write the reaction of ethanol with sodium.
  17. What is dehydration of alcohol?
  18. State the oxidation products of 1°, 2° and 3° alcohols.
  19. What is catalytic dehydrogenation?
  20. Define esterification with an example.
  21. Describe the iodoform test of ethanol.

Long-Answer Questions

  1. Explain nomenclature, classification and isomerism of monohydric alcohols.
  2. Describe Victor Meyer’s method for distinguishing primary, secondary and tertiary alcohols.
  3. Describe preparation of monohydric alcohols from haloalkanes, primary amines and esters.
  4. Explain industrial preparation of alcohol by oxo process, hydroboration–oxidation and fermentation.
  5. Explain the common terms absolute alcohol, power alcohol, denatured alcohol, rectified spirit and alcoholic beverage.
  6. Explain physical properties of alcohols on the basis of hydrogen bonding.
  7. Describe reactions of alcohols with HX, PCl₃, PCl₅ and SOCl₂.
  8. Explain dehydration of alcohols with a suitable example.
  9. Compare oxidation of primary, secondary and tertiary alcohols.
  10. Explain catalytic dehydrogenation of primary and secondary alcohols and dehydration of tertiary alcohols.
  11. Explain esterification with an example.
  12. Describe the iodoform test of ethanol, including observation and equation.

Conversion Questions

  1. Bromoethane → ethanol.
  2. Ethylamine → ethanol.
  3. Ethanol → bromoethane.
  4. Ethanol → chloroethane using SOCl₂.
  5. Ethanol → sodium ethoxide.
  6. Ethanol → ethene.
  7. Ethanol → ethanal → ethanoic acid.
  8. Propan-2-ol → propanone.
  9. Ethanol + ethanoic acid → ethyl ethanoate.
  10. Glucose → ethanol.

Diagram Questions

  1. Draw the classification of 1°, 2° and 3° alcohols.
  2. Draw the Victor Meyer test flowchart.
  3. Draw a preparation map from haloalkane, primary amine and ester.
  4. Draw the oxo-process flow diagram.
  5. Draw hydroboration–oxidation of ethene.
  6. Draw the fermentation process.
  7. Draw intermolecular hydrogen bonding between alcohol molecules.
  8. Draw the oxidation map of 1°, 2° and 3° alcohols.
  9. Draw the catalytic behaviour of alcohols over heated copper.
  10. Draw the iodoform test observation for ethanol.
Exam Strategy For alcohol reactions, always identify the class of alcohol, reagent, condition and organic product. For oxidation questions, first decide whether the alcohol is 1°, 2° or 3° before predicting the product.

20. One-Minute Revision

  • Alcohols have –OH bonded to an sp³ carbon; general form R–OH.
  • Monohydric alcohols contain one –OH group.
  • 1°, 2° and 3° classification depends on the carbon bearing –OH.
  • Victor Meyer: primary gives red, secondary gives blue, tertiary gives no characteristic red/blue colour.
  • Haloalkane + aqueous KOH gives alcohol.
  • Primary amine + HNO₂ gives alcohol + N₂.
  • Ester hydrolysis can produce an alcohol.
  • Oxo process: alkene → aldehyde → alcohol.
  • Hydroboration–oxidation converts alkene to alcohol.
  • Fermentation: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.
  • Absolute alcohol is nearly water-free; rectified spirit is concentrated ethanol–water mixture.
  • Alcohols hydrogen-bond, giving relatively high boiling points.
  • 2ROH + 2Na → 2RONa + H₂.
  • Dehydration gives an alkene + water.
  • 1° oxidation: aldehyde then acid.
  • 2° oxidation: ketone.
  • 3° alcohols resist mild oxidation.
  • Heated Cu: 1° → aldehyde + H₂; 2° → ketone + H₂.
  • Esterification: alcohol + carboxylic acid ⇌ ester + water.
  • Ethanol gives yellow CHI₃ in the iodoform test.

21. Diagram Practice

Students should practice these diagrams for the NEB examination:

  1. Classification of primary, secondary and tertiary alcohols.
  2. Victor Meyer’s method flowchart.
  3. Preparation of alcohol from haloalkane, amine and ester.
  4. Oxo-process flow diagram.
  5. Hydroboration–oxidation of ethene.
  6. Fermentation of glucose to ethanol.
  7. Hydrogen bonding between alcohol molecules.
  8. Dehydration of alcohol to alkene.
  9. Oxidation map of 1°, 2° and 3° alcohols.
  10. Catalytic dehydrogenation/dehydration pattern.
  11. Iodoform test of ethanol.
Source handling: The original Nepal eNotes PDF remains embedded above. The typed section follows the verified NEB/CDC syllabus and is designed as a searchable, responsive study companion. Where the PDF viewer does not expose handwritten page text, the typed section is a syllabus-aligned reconstruction and is not claimed to be a word-for-word transcription.

Discussion

Share a helpful question, idea, or explanation with other students.

Leave a Comment

Write a clear question, answer, or helpful explanation.
Your email will not be published.

Download Our Offline App

Study class-wise notes even when internet is not available. Get the app from Play Store.

Nepal eNotes offline app preview
Get it on Google Play